Got this from a other forum and at 500 treads in 2 days there is no concensus. The two answers is 2 and 288. Calculated as follows 48/2(9+3)= 48/(18+6)= 48/24=2 or 48/2(9+3)= 24x(9+3)= 24x12=288 IMO the answers is 2.
yes, id say 48/2(12) 48/24 2 i think this is wrong because i'd get: 48/2(9+3)= 24/(9+3)= 24/12=2 this is right
oh i see.. depends on what it means.. if its (48/2)(9+3) then this is 288 if its 48/(2(9+3)) then its 2
Correct answer is 288. 48/2(9+3) You do the brackets first so 48/2(12) But remember 2(12) doesn't count as "brackets" in BODMAS/BOMDAS, it's actually 2 x (12) So we have: 48 / 2 x 12 With division and multiplication being on the same level we do it from left to right. 24 x 12 288
yes but what if its a=(9+3) so 48/2a = 24/a = 24/12 = 2? you cant say that 48/2(9+3) is the same as 48/2x(9+3)
i think that the problem is that its not written in proper mathematical format.. because if written differently, it is different answers: so i say 48/2(9+3) is ambiguous which means the answer is 288 and 2? hehe
I suppose it is ambiguous to a degree, but if you want the top version to be correct you would have to put parentheses around the 48/2. The way it is written, we first resolve the 2(9+3) to 24, and then perform the division.
In step 4 you would factor out the "a" to "a(a + b)". Dividing 2a(squared) by "a" gives you 2a = a + b.
well its because you are starting with the wrong definition. a = b is false if a=b then this means that b=a which means that a=a and b=b so obviously if u start out with a=b the overall equation will be wrong clever though.. took me a few mins
so if a=b and you subs into the equation in the last line 2(a(sq)-ab) = 1(a(sq)-ab) then this will give you 2((b(sq)-b(sq)) = 1 ((b(sq)-b(sq)) 2(0) = 1(0) 0=0 which is correct.. i rem something abt this sum in maths at varsity.. cant rem now.. hmm
2(9+3) means addition inside the bracket FIRST, no sign between '2' and bracket, means multiplication. so its 48/24 = 2 a,b,c,d,e does not constitute 1,2,3,4,5 in a proof, they are basically UNKNOWNS, so A = B, is 1=1 or 2=2 or 3=3 or 4=4 or 5=5... NOT 1=2
oh i think it was that you not allowed to cancel out all variables of the equation! yes.. else answer will be incorrect.. so if you were left with a= something or b= something it would be right?? something like that.. Math was so long ago hehe